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2x^2-182=0
a = 2; b = 0; c = -182;
Δ = b2-4ac
Δ = 02-4·2·(-182)
Δ = 1456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1456}=\sqrt{16*91}=\sqrt{16}*\sqrt{91}=4\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{91}}{2*2}=\frac{0-4\sqrt{91}}{4} =-\frac{4\sqrt{91}}{4} =-\sqrt{91} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{91}}{2*2}=\frac{0+4\sqrt{91}}{4} =\frac{4\sqrt{91}}{4} =\sqrt{91} $
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